A promoter priced tickets to a concert as follows: $17 when purchased in advance and $20 purchased at the door. The total number of tickets purchased was 514, and the ticket sales totaled $9,158. How many tickets were sold at the door?
A: 140
B: 374
C: 514
D: 420
You need to turn this into a pair of simultaneous equations thus:
Number of Advance tickets = A
Number of Door tickets = D.
Total number of tickets = A + D = 514………equation 1
Advance tickets cost $17 so takings for these = 17*A or 17A
Door tickets cost $20 so takings for these = 20*D or 20D
total takings = 17A + 20D = 9158……..equation 2
Multiply Equation 1 by 20 to give 20A+20D=10280
Subtract Equation 2………………….17A+20D=9158
3A = 1122
so A = 374
If 374 tickets were sold in advance, 514 – 374 = 140 were sold on the door. Answer A, your friend is right.
You need to turn this into a pair of simultaneous equations thus:
Number of Advance tickets = A
Number of Door tickets = D.
Total number of tickets = A + D = 514………equation 1
Advance tickets cost $17 so takings for these = 17*A or 17A
Door tickets cost $20 so takings for these = 20*D or 20D
total takings = 17A + 20D = 9158……..equation 2
Multiply Equation 1 by 20 to give 20A+20D=10280
Subtract Equation 2………………….17A+20D=9158
3A = 1122
so A = 374
If 374 tickets were sold in advance, 514 – 374 = 140 were sold on the door. Answer A, your friend is right.
d 420
A 140